dear readers, here I am telling you the shortcut trick of
the square root upto infinity problem- substraction- which is asked in most
competitive exams like cat, afcat, mat, gate, ssc, ibps etc.

Before learning to solve this question,
you should know about the addition version of this question type. I have
discussed that in my recent post. Please read that post first before reading
this post by clicking here.

So friends, here we are given a question
in which we have to calculate the square root of 12 with simultaneously
decreasing it with square root of 12 successively.

What we normally do is calculating the value of square root of 12 and then adding it successively until we reach a near value. But that process takes a lot of time.

What we normally do is calculating the value of square root of 12 and then adding it successively until we reach a near value. But that process takes a lot of time.

So here I am telling you about a trick
through which you can easily do this question in just 2 seconds.

I am explaining the solution of this
problem here.

Solution:

Assume 12 as x, remember x should be
given even for this trick to work. If x is given odd, then the formula of the
trick will change.

Now think of two consecutive factors of
12. i.e.

12=n(n+1)

The value of n will be the answer of this
type of problem.

12=3(3+1)

12=3*4

The shorter value means 3 will be the
answer.

Note: in addition (+)version of this type
of problems, the bigger factor means n+1 will be the answer while in
subtraction version of this problem, n
will be the answer.