here is time and distance problems shortcut formula #2.
Through this tricky formula, you will be able to solve this type of question in
seconds.

Suppose you are given a question like this

A student reaches his home from school late by 30 minutes
from his scheduled if he walks at a speed of 5 km/h. but if he walks at a speed
of 6 km/h, he will reach his home 5 minutes early. What will be the distance
from school to home.

These questions are asked in many competitive exams and
other exams. Students usually solve these questions by their own shortcut
methods but their shortcut method takes time of about minimum 1 minute. But
here is a shortcut trick for this type of question which will make this
question easy to solve as you can solve this question in just 10 seconds or
less. You just have to put the formula of our trick into the question and you
have got the answer.

So here is the rule for this type of question.

Rule- if a person reaches his destination t1 time early by
walking at a speed of x and t2 time later by walking at a speed of y, then the
distance between both places is

={xy(t1+t2)}/{(x-y)60}

Now equate the question given above to the rule also given
just above.

Now t1=30 minutes,
t2=5 minutes

And x=5 km/h, y= 6 km/h

The distance will be
then

={(30+5)5X6}/(5-6)60

=
(35X5X6)/1X60

=
17.5 km answer

CLICK HERE FOR TIME AND DISTANCE TRICK #3
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ReplyDelete