This time we are giving you the Shortcut Formulas trick of Time and Work problems with formulas and most commonly asked questions shortcut trick.

Formulas

If a person can do a piece of work in x days, then the work
done by that person in one person

is 1/x.
And

If the work done by a person in one day is 1/x then he will
complete the work in x days.

If A and B do a work in different amounts of time, then

A’s work: B’s work = time taken by B : time
taken by A

If the efficiency of A is x times to that of B, then time
taken by A is 1/x times to that of B.

If A and B can do a work in x days and A alone can do that work
in y days, then B can do that work in

=xy/(y-x)
days

If A can do a type of work in x days and B can do that work
in y days, then both will complete the work together in

=xy/(x+y)
days

Also read time and work shortcut trick #4

time and work shortcut trick #3

Below are More Shortcut Formulas for Time and Work Problems

Also read time and work shortcut trick #4

time and work shortcut trick #3

Below are More Shortcut Formulas for Time and Work Problems

If A, B and C can do a work in x, y and z days respectively,
then all of them together will complete that work in xyz/(xy+yz+zx) days

If A and B can do a work in x days, B and C can do a work in
y days and C and A can do that same work in z days, then all of them working together
will complete the work in

2xyz/(xy+yz+zx)

If A can do a work in x days and B can do that work in y
days. A and B, they started that work together but A left n days before the
completion of the work and B alone have to complete the work. Then B will
complete that work in

y(x+n)/(x+y)
days

if A can do a work in
x days, B can do that work in y days and C can do that work in z days. All of
them started the work together but A left after n days before the completion of
the work. So B and C together will complete
the remaining work in

yz(n+x)/(xy+yz+zx)
days

example:

Ram and Shyam can do a piece of work in 10 days and 20 days
respectively. Both of them started the work together but Ram left after 5 days
before the completion of the work. So in how many days will the work be completed?

Solution:

Here x= 10 days

And y= 20 days

And n= 5 days

So putting the formula of determining the time taken given
above to complete the work:

=y(x+n)/(x+y)

=20(10+5)/(10+20)

= 10
days

also read Time Management for SSC IBPS exams

below is another Shortcut Formula for Time and Work Questions

also read Time Management for SSC IBPS exams

below is another Shortcut Formula for Time and Work Questions

Example 2:

If A can complete a work in 10 days and B can
complete that same work in 15 days, then, in how many days both of them
together can complete the same work.

So putting the formula for above type of question, x=10, y=
15

here, = xy/ x+ y = 10 × 15/ (10+15) = 150/25= 6 days. Ans.

The work will be completed in 6 days.

So you just have to put the formula and you will get the
answer.

i think the first example and "A can do a piece of work in 12 days and B can do the same piece of work in 18 days. Both of them worked together for two days. After 2 days, A left the work. So B has to complete the remaining work by himself. So how long will B take to complete the remaining work?" are same but the first example solved by the "y(x+n)/(x+y)" and the second is solved by "y-[P(x+y)/x]" why...????? i am confuseing in this....

ReplyDeletethe formula in which this formula y(x+n)/(x+y) is given are those questions in which A or B leaves before P days before completion of work. but in the formula y-[P(x+y)/x] is for those questions in which A left after working for P days. that's the difference between both........

Deleteok sir thank you very much :)

DeleteBut many times its harder to remember many formulas for every questions

ReplyDelete