RANKING TEST REASONING SHORTCUT TRICKS

Ranking test questions are asked in many competitive
examinations including SSC, IBPS etc. in reasoning section. Reasoning is a very important section as it let you score more if you know the shortcuts.

If a candidate do not know the shortcut tricks to solve these problems, then it might take some of their extra time in solving. But since time is a crucial factor in qualifying these SSC IBPS etc. competitive exams, so we have to learn a few shortcut tricks to solve questions quickly in seconds. There is no formula you have to remember to solve these problems. So here are Ranking Test shortcut tricks to help you solve ranking test problems.

If a candidate do not know the shortcut tricks to solve these problems, then it might take some of their extra time in solving. But since time is a crucial factor in qualifying these SSC IBPS etc. competitive exams, so we have to learn a few shortcut tricks to solve questions quickly in seconds. There is no formula you have to remember to solve these problems. So here are Ranking Test shortcut tricks to help you solve ranking test problems.

Starting from easy questions then moving to difficult ones.

Suppose you are given a question like the one given below:

Type -1: Rajesh is 12

^{th}from both ends of a row. How many candidates are there in the row?
This is an Easy problem.

Since Rajesh is 12 from both sides of the row. It means 11
persons are to his left and 11 are to his right. He is 12

^{th}from both ends. So total candidates are 11+1+11=23 candidates Ans.
Let us move on to little difficult problem now.

Type -2: Sahib is 12

^{th}from left and 15^{th}from right end of a row. How many persons are there in the row?
Shortcut trick to the solution of the problem is simple.

Just add the two given numbers and subtract 1 from them. You
will find the number of person in the row.

Total persons in the row= 12+15-1=26 persons.

Let us move on to more difficult problems now.

Type -3: Mukesh and Suresh are standing in a queue. Mukesh
is 9

^{th}from left and Suresh is 6^{th}from right. When both interchange their positions, Mukesh becomes 15^{th}from left. Find out new position of Suresh from right end.
Ranking test Shortcut trick to solve this problem is given
below.

Mukesh’s position changes from 9

^{th}to 15^{th}from left end. So there is an increase of 6 ranks. Since Mukesh and Suresh both interchanged their positions, so there must be the same increase in rank of Suresh position from right.
So Suresh position= 6+6=12

^{th}from right Ans.
So determine the increase or decrease in position of common
end and add the increase or subtract the decrease.

WE HAVE MANY AWESOME SHORTCUT TRICKS FOR ALL COMPETITIVE EXAMS. FOR THEM, See SITEMAP given on top of site.

Type -4: Sonu and Monu are standing in a row of boys. Sonu is
14

^{th}from left and Monu is 7^{th}from right. If both interchange their positions, Monu becomes 15^{th}from the right. Find out the total number of boys in that row.
The ranking test problem can easily be solved by the shortcut
trick given below.

Find out the common person who’s position is given two
times. In this question, Monu’s position changes from 7 to 15 from right. Since
he is at 15

^{th}position after interchanging, so it means 14 boys are to his right. Now Monu is at Sonu’s position which is 14^{th}from left means 13 boys are to his left.
Add all these left and right means 14+13+1(Monu’s own
position)= 28 boys in row Ans.

I hope now you understand these ranking test shortcut tricks
and can easily solve these problems. If you like this ranking test shortcut
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